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Fundamentals · about 15 minutes

Series and Parallel Circuits

Loads can share one path or each get a path of their own. That choice decides how bright lamps glow, what happens when one fails and how much current the circuit draws.

You will learn:

  • Series rules: one current, shared voltage
  • Parallel rules: one voltage, shared current
  • How opens and shorts behave in each
  • How an overload trips a breaker

Two ways to connect loads

In a series circuit, current passes through every load in turn. There is only one path, so whatever flows through the first load flows through all of them.

In a parallel circuit, each load sits on its own branch connected across the same two points. The current divides between the branches, and each branch works on its own.

Series circuits

  • The same current flows through every load.
  • The voltages across the loads add up to the supply voltage.
  • Total resistance is the sum of the individual resistances: R total = R1 + R2 + R3.

Three 40 Ω lamps in series on 120 V

Given: 120 V supply; Three lamps of 40 Ω each

  1. R total = 40 + 40 + 40 = 120 Ω
  2. I = V ÷ R = 120 ÷ 120 = 1 A
  3. Voltage across each lamp = I × R = 1 × 40 = 40 V

Answer: 1 A through every lamp, 40 V across each

Each lamp gets only part of the supply voltage, so lamps rated for 120 V glow dimly when wired in series. A larger resistance takes a larger share of the voltage, because the same current flows through every load.

Parallel circuits

  • Every branch gets the full supply voltage.
  • The branch currents add up to the total current drawn from the supply.
  • Total resistance is lower than the smallest branch: 1 ÷ R total = 1 ÷ R1 + 1 ÷ R2 + 1 ÷ R3.

The same lamps in parallel on 120 V

Given: 120 V supply; Three lamps of 40 Ω each

  1. Current in each branch = 120 ÷ 40 = 3 A
  2. Total current = 3 + 3 + 3 = 9 A
  3. R total = 120 ÷ 9 ≈ 13.3 Ω

Answer: 3 A through each lamp, 9 A from the supply

Every lamp now gets the full 120 V and glows at full brightness, and the circuit draws nine times the current of the series version.

R total = (R1 × R2) ÷ (R1 + R2)
A shortcut for two branches. Two 60 Ω loads in parallel make 30 Ω.

Compare them side by side

Both circuits below use the same supply and the same three lamps. Change a lamp's resistance, open a branch, burn out or short a lamp, and compare the readings. Tap any part of either drawing to see what it does.

Interactive: Series and parallel circuits

Three lamps wired in series and the same three lamps wired in parallel, each circuit fed from an adjustable supply through a 15 A breaker. Every lamp shows its voltage, current and power, and any lamp can be burned out or shorted. The simulator runs in your browser with JavaScript turned on.

Why buildings are wired in parallel

Receptacles and lights in a building are connected in parallel. Each device gets the full circuit voltage and can be switched on and off without affecting the others. When one lamp fails, the rest of the room stays lit.

Series connections still show up on every job. A switch is always in series with the load it controls, and a fuse or breaker is in series with everything on its circuit. Some decorative light strings are wired in series too, which is why one loose or missing bulb can darken a whole section.

Opens and shorts

Most troubleshooting comes down to two kinds of fault.

  • Open circuit. A break in the path, such as a burned-out filament, a broken conductor or a loose termination. In a series circuit, one open stops current everywhere. In a parallel circuit, an open inside one branch stops only that branch. An open in the shared conductors stops everything past it, which is how one loose connection can leave every receptacle downstream without power.
  • Short circuit. A path with almost no resistance, such as damaged insulation where conductors touch. Current rises far above normal until the breaker or fuse opens. A short across one load in a series circuit leaves the other loads carrying more current, so they glow brighter.

In a series circuit with a single open, the full supply voltage appears across the break, while the working loads read close to zero volts because no current flows through them. That reading points straight at the fault. In a parallel circuit, a burned-out lamp still has the full supply voltage across its terminals, and its branch simply draws no current.

Challenge: Predict the burnout

Lamp 2 burns out. Predict which lamps stay lit in the series circuit and in the parallel circuit, then check.

Overloads and the breaker

Each load added in parallel adds current. Lower the lamp resistances in the parallel circuit until the total passes 15 A and the breaker trips.

How many 100 W lamps on one circuit?

Given: 120 V, 15 A circuit; 100 W lamps

  1. Each lamp draws 100 ÷ 120 ≈ 0.83 A
  2. 15 ÷ 0.833 = 18 lamps

Answer: 18 lamps reach the breaker rating

Real breakers respond on a time curve. A small overload can run for many minutes, or even hours, before the breaker trips, while a short circuit trips it almost instantly. The simulator trips the moment the current passes the rating so the cause is easy to see.

Challenge: Trip the breaker

Lower the resistances in the parallel circuit until the breaker trips, then read the current that tripped it.

Check your understanding

1. Three identical lamps are wired in series and one burns out. What happens to the other two?

Answer: They go out. A series circuit has one path. The burned-out filament breaks it, so no current flows anywhere.

2. The same three lamps are wired in parallel and one burns out. What happens to the other two?

Answer: They stay lit at the same brightness. Each branch still has the full supply voltage, so the other lamps carry the same current as before.

3. What is the total resistance of 10 Ω, 20 Ω and 30 Ω in series?

Answer: 60 Ω. In series the resistances add: 10 + 20 + 30 = 60 Ω.

4. What is the total resistance of two 60 Ω resistors in parallel?

Answer: 30 Ω. (60 × 60) ÷ (60 + 60) = 3600 ÷ 120 = 30 Ω. Two equal branches always halve the resistance.

5. A series circuit has one open. Where does a voltmeter read the full supply voltage?

Answer: Across the open. With no current flowing, the working loads drop no voltage, so the entire supply voltage appears across the break.

Where this knowledge gets used

Lessons are free study material. Finishing one does not certify a skill, count toward a license or replace hands-on training under qualified supervision.