Home > Electrical Learning Lab > Ohm's law

Fundamentals · about 12 minutes

Ohm's Law: Voltage, Current and Resistance

Ohm's law connects voltage, current and resistance, the numbers behind every circuit an electrician works on. Change them on the circuit below and see how each one moves the others.

You will learn:

  • V = I × R and what each letter means
  • Solving for current, voltage or resistance
  • Power in watts: P = V × I
  • Why a loose connection runs hot

What Ohm's law says

In a circuit made of resistance, the current equals the voltage divided by the resistance. Rearranged, that becomes the formula most electricians learn first: V = I × R.

  • Voltage (V) is the electrical pressure that pushes current around a circuit. It is measured in volts.
  • Current (I) is the rate at which charge flows past a point. It is measured in amperes, usually shortened to amps.
  • Resistance (R) is how strongly a material opposes that flow. It is measured in ohms, written with the symbol Ω.

Raise the voltage across a fixed resistance and the current rises with it, in direct proportion. Raise the resistance at a fixed voltage and the current falls. Every calculation in this lesson comes back to those two facts.

The letter I comes from intensité, the French term for current intensity used by André-Marie Ampère. It is easy to confuse with the number 1, so write it clearly on a job sheet.

Try it on a working circuit

The circuit below has a voltage source, a resistor, an ammeter in line with the current and a voltmeter across the resistor. Choose which value to solve for, then move the other two. Tap any part of the drawing to see what it does.

Interactive: Ohm's law circuit

An adjustable voltage source drives current through a resistor. Set any two of voltage, current and resistance and the circuit calculates the third, along with the power the resistor turns into heat. The simulator runs in your browser with JavaScript turned on.

The moving dashes show how much current is flowing: more current, faster dashes. They follow conventional current, which runs from the positive terminal through the load and back to the negative terminal. The electrons themselves drift the opposite way, and far more slowly than the animation suggests.

Solving for any one value

Because V = I × R is a simple product, you can rearrange it to find whichever value is missing.

I = V ÷ R
Current equals voltage divided by resistance.
R = V ÷ I
Resistance equals voltage divided by current.
V = I × R
Voltage equals current times resistance.

A quick memory aid is the Ohm's law triangle: V on top, with I and R side by side underneath. Cover the value you want to find. What remains shows the math, either a division (V over I, or V over R) or a multiplication (I beside R).

Finding current

Given: 12 V supply; 4 Ω load

  1. I = V ÷ R
  2. I = 12 ÷ 4

Answer: 3 A

Finding resistance

Given: 120 V measured across a coffee maker element; 10 A measured with a clamp meter

  1. R = V ÷ I
  2. R = 120 ÷ 10

Answer: 12 Ω

Finding voltage

Given: 2 A flowing; 60 Ω resistor

  1. V = I × R
  2. V = 2 × 60

Answer: 120 V

Challenge: Hit the target current

With a 60 Ω resistor in the circuit, set the supply voltage so exactly 2 A flows.

Challenge: Size up a water heater element

A 240 V water heater element draws 18.75 A. Work out its resistance, then check your answer.

Power: what the circuit does with the energy

For a resistive load, voltage and current together tell you how much power it uses, measured in watts. A resistor turns that power into heat, which is what a heater element is built to do.

P = V × I
Power equals voltage times current.

Substituting Ohm's law gives two more forms of the same formula: P = I² × R and P = V² ÷ R. Use whichever one matches the numbers you have.

A space heater

Given: 1500 W heater; 120 V circuit

  1. I = P ÷ V
  2. I = 1500 ÷ 120

Answer: 12.5 A

That is most of a 15 A circuit for one appliance. Plug a 1500 W hair dryer into the same circuit and the total climbs to 25 A, well past the breaker rating, so the breaker trips.

Why loose connections run hot

Ohm's law explains one of the most common causes of electrical fires. A loose, corroded or undertightened connection adds resistance at a point where there should be almost none, and every amp of load current has to pass through it.

A loose lug

Given: 20 A of load current; 0.1 Ω of extra resistance at one terminal

  1. Voltage lost at the terminal: V = I × R = 20 × 0.1 = 2 V
  2. Heat at the terminal: P = I² × R = 20² × 0.1 = 40 W

Answer: 40 W of heat in one small connection

Forty watts spread across a light bulb is ordinary. Forty watts concentrated in a single screw terminal can discolor insulation, loosen the connection further and eventually start a fire. Because the heat rises with the square of the current, the same bad connection produces four times the heat when the current doubles.

Measuring the voltage drop across a connection under load is a standard way to find these problems: a sound connection drops almost nothing, while a reading across a single terminal points to added resistance. That measurement is made on energized equipment, so it is work for qualified people using rated meters and the right protective equipment.

Where the simple model stops

Ohm's law describes resistive loads well. A few things change the picture in real installations.

  • Temperature. Resistance changes as materials heat up. A cold incandescent filament has a small fraction of its hot resistance, so the bulb draws a surge of current the instant it turns on.
  • Alternating current with reactance. Motors, transformers and capacitors add reactance, and the combined opposition to current is called impedance (Z). The same idea holds, written V = I × Z. For these loads, volts times amps gives volt-amperes (VA). Multiply by the power factor, a number below 1, to get the real power in watts.
  • Electronic loads. LED drivers, chargers and variable speed drives do not draw current in proportion to the voltage, so no single resistance value describes them.

For purely resistive loads on alternating current, such as heaters and incandescent lamps, Ohm's law works with the RMS values a meter reads. That is why the 120 V examples in this lesson hold up.

Check your understanding

1. A 24 V circuit has 8 Ω of resistance. How much current flows?

Answer: 3 A. I = V ÷ R = 24 ÷ 8 = 3 A.

2. You measure 120 V across a heating element and 8 A through it. What is its resistance?

Answer: 15 Ω. R = V ÷ I = 120 ÷ 8 = 15 Ω.

3. The voltage stays the same and the resistance doubles. What happens to the current?

Answer: It drops to half. Current is voltage divided by resistance, so twice the resistance gives half the current.

4. How much current does a 1200 W hair dryer draw on 120 V?

Answer: 10 A. I = P ÷ V = 1200 ÷ 120 = 10 A.

5. A connection with 0.05 Ω of extra resistance carries 30 A. How much heat does it produce?

Answer: 45 W. P = I² × R = 30² × 0.05 = 900 × 0.05 = 45 W.

Where this knowledge gets used

  • Journeyman openings: Journeymen use these numbers every day, from checking a load to tracking down heat at a bad connection.
  • Starting out in the trade: How registered apprenticeships work, what they ask of you and how long they take.
  • Pay by market: See what electrical work pays in the markets near you.

Lessons are free study material. Finishing one does not certify a skill, count toward a license or replace hands-on training under qualified supervision.